400 cm of sodium hydroxide solution 0.5 mol dm 3 is used to neutralise 100 cm of hydrochloric
acid solution as shown in the reaction below.
NaOH(aq) + HCl(aq) - NaCl(aq) + H2O(1)
4
What is the concentration of the hydrochloric acid solution?
A 0.100 mol dm3
С 1.00 mol dm3
B 0.200 mol dm3
D 2.00 mol dm3
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acid solution as shown in the reaction below.
NaOH(aq) + HCl(aq) - NaCl(aq) + H2O(1)
4
What is the concentration of the hydrochloric acid solution?
A 0.100 mol dm3
С 1.00 mol dm3
B 0.200 mol dm3
D 2.00 mol dm3
Jawaban:
D. 2,00 mol/dm³
Penjelasan:
V NaOH = 400 cm³ = 0,4 dm³
M NaOH = 0,5 mol/dm³ or 0,5 M
V HCl = 100 cm³ = 0,1 dm³
Reaction:
NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)
Ask: concentration of HCl?
answer:
neutralise equation is:
Va x Ma x a = Vb x Mb x b
0,1 dm³ x Ma x 1 = 0,4 dm³ x 0,5 M x 1
0,1 dm³ x Ma = 0,2 mol
Ma = 0,2 mol / 0,1 dm³ = 2,00 M or 2,00 mol/dm³
nb:
cm³ = ml
dm³ = L
cmiiw ^^
